Results
| WTA Huzhou | 09/08 08:00 | 25 |
[218] Carol Zhao v
Sijia Wei
[184] 
|
3-6,3-6 | |
| WTA Changsha | 09/03 02:00 | 26 |
[230] Ekaterina Reyngold
v
Carol Zhao [250]
|
6-4,6-2 | |
| WTA Changsha | 09/02 02:30 | 25 |
[242] Zarina Diyas
v
Carol Zhao [250]
|
Retired | |
| US Open Women | 08/21 22:15 | 15 |
[230] Carol Zhao v
Lucrezia Stefanini
[149] 
|
1-6,4-6 | |
| US Open Women | 08/19 17:20 | 14 |
[118] Maria Lourdes Carle
v
Carol Zhao [230]
|
6-7,2-6 | |
| WTA Cincinnati | 08/06 16:50 | 14 |
[98] Leolia Jeanjean
v
Carol Zhao [219]
|
6-1,4-6,6-3 | |
| WTA Montreal | 07/26 18:05 | 14 |
[96] Elsa Jacquemot
v
Carol Zhao [225]
|
6-0,3-6,6-4 | |
| ITF W100 Evansville | 07/24 15:00 | - |
[225] Carol Zhao v
Janice Tjen
[204] |
4-6,2-6 | |
| ITF W100 Evansville | 07/22 18:00 | - |
[476] Sara Daavettila
v
Carol Zhao [225]
|
5-7,3-6 | |
| ITF W75 Granby | 07/17 14:00 | - |
[232] Carol Zhao v
Fiona Crawley
[411] |
7-6,3-6,5-7 | |
| ITF W75 Granby | 07/16 14:00 | - |
[170] Mia Kupres
v
Carol Zhao [232]
|
4-6,3-6 | |
| WTA Newport | 07/12 20:55 | 28 |
[45] Tatjana Maria
v
Carol Zhao [273]
|
6-1,6-2 |
Wikipedia - Carol Zhao
Carol Zhao (born June 20, 1995) is a Chinese-Canadian tennis player. She reached her highest WTA singles ranking of No. 131 in June 2018, and her career-high junior rank of No. 9 on January 1, 2013. She won the Australian Open junior doubles title in 2013. Zhao was a member of the Stanford University tennis team, ending her college career with a 76–16 overall record and leading the team to win the 2016 NCAA championship. She also was the 2015 NCAA singles runner-up.
She turned professional in June 2016 and was Canada's top singles player from June 11, 2018, to July 23, 2018.